w+3=1/6(w-12)

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Solution for w+3=1/6(w-12) equation: 



w+3=1/6(w-12)

We move all terms to the left:

w+3-(1/6(w-12))=0



Domain of the equation: 6(w-12))!=0

w∈R



We multiply all the terms by the denominator


w*6(w-12))-(1+3*6(w-12))=0

Wy multiply elements

6w^2(w+18w(w=0

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