w-1/5+3=w+6/2

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Solution for w-1/5+3=w+6/2 equation: 


w in (-oo:+oo)

w-(1/5)+3 = w+6/2 // - w+6/2

w-w-(1/5)-(6/2)+3 = 0

w-w-1/5-3+3 = 0

-1/5 = 0

w belongs to the empty set

w belongs to the empty set

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