w-3+2(4w+3)=-3(w-2)

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Solution for w-3+2(4w+3)=-3(w-2) equation: 



w-3+2(4w+3)=-3(w-2)

We move all terms to the left:

w-3+2(4w+3)-(-3(w-2))=0

We multiply parentheses

w+8w-(-3(w-2))+6-3=0



We calculate terms in parentheses: -(-3(w-2)), so:

-3(w-2)

We multiply parentheses

-3w+6

Back to the equation:

-(-3w+6)



We add all the numbers together, and all the variables

9w-(-3w+6)+3=0

We get rid of parentheses

9w+3w-6+3=0

We add all the numbers together, and all the variables

12w-3=0

We move all terms containing w to the left, all other terms to the right

12w=3

w=3/12

w=1/4

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