w-3/w+3+w-6/w+2+2

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Solution for w-3/w+3+w-6/w+2+2 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w+w-(3/w)-(6/w)+2+2+3 = 0

w+w-3*w^-1-6*w^-1+2+2+3 = 0

2*w^1-9*w^-1+7*w^0 = 0

(2*w^2+7*w^1-9*w^0)/(w^1) = 0 // * w^2

w^1*(2*w^2+7*w^1-9*w^0) = 0

w^1

2*w^2+7*w-9 = 0

2*w^2+7*w-9 = 0

DELTA = 7^2-(-9*2*4)

DELTA = 121

DELTA > 0

w = (121^(1/2)-7)/(2*2) or w = (-121^(1/2)-7)/(2*2)

w = 1 or w = -9/2

w in { -9/2, 1} 

w in { -9/2, 1 }

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