w-3/w-5+1=w+2/w-4

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Solution for w-3/w-5+1=w+2/w-4 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w-(3/w)-5+1 = w+2/w-4 // - w+2/w-4

w-w-(3/w)-(2/w)-5+1+4 = 0

w-w-3*w^-1-2*w^-1-5+1+4 = 0

-5*w^-1 = 0 // : -5

w^-1 = 0

w naleu017Cy do O

w belongs to the empty set

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