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w-4/5w-13=-2
We move all terms to the left:
w-4/5w-13-(-2)=0
Domain of the equation: 5w!=0We add all the numbers together, and all the variables
w!=0/5
w!=0
w∈R
w-4/5w-11=0
We multiply all the terms by the denominator
w*5w-11*5w-4=0
Wy multiply elements
5w^2-55w-4=0
a = 5; b = -55; c = -4;
Δ = b2-4ac
Δ = -552-4·5·(-4)
Δ = 3105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3105}=\sqrt{9*345}=\sqrt{9}*\sqrt{345}=3\sqrt{345}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-3\sqrt{345}}{2*5}=\frac{55-3\sqrt{345}}{10} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+3\sqrt{345}}{2*5}=\frac{55+3\sqrt{345}}{10} $
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