w-4/w-2+1=w-3/w+2

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Solution for w-4/w-2+1=w-3/w+2 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w-(4/w)-2+1 = w-(3/w)+2 // - w-(3/w)+2

w-w-(4/w)+3/w-2-2+1 = 0

w-w-4*w^-1+3/w-2-2+1 = 0

-1*w^-1 = 3 // : -1

w^-1 = -3

-1 < 0

1/(w^1) = -3 // * w^1

1 = -3*w^1 // : -3

-1/3 = w^1

w = -1/3

w = -1/3

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