w2+13w+36=(w+4)(w+)

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Solution for w2+13w+36=(w+4)(w+) equation: 



w2+13w+36=(w+4)(w+)

We move all terms to the left:

w2+13w+36-((w+4)(w+))=0

We add all the numbers together, and all the variables

w2+13w-((w+4)(+w))+36=0

We add all the numbers together, and all the variables

w^2+13w-((w+4)(+w))+36=0

We multiply parentheses ..

w^2-((+w^2+4w))+13w+36=0



We calculate terms in parentheses: -((+w^2+4w)), so:

(+w^2+4w)

We get rid of parentheses

w^2+4w

Back to the equation:

-(w^2+4w)



We add all the numbers together, and all the variables

w^2+13w-(w^2+4w)+36=0

We get rid of parentheses

w^2-w^2+13w-4w+36=0

We add all the numbers together, and all the variables

9w+36=0

We move all terms containing w to the left, all other terms to the right

9w=-36

w=-36/9

w=-4

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