w2+15w+35=0

Solution for w2+15w+35=0 equation:

w2+15w+35=0

We add all the numbers together, and all the variables

w^2+15w+35=0

a = 1; b = 15; c = +35;
Δ = b2-4ac
Δ = 152-4·1·35
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{85}}{2*1}=\frac{-15-\sqrt{85}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{85}}{2*1}=\frac{-15+\sqrt{85}}{2}
$