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w2+16=8w
We move all terms to the left:
w2+16-(8w)=0
We add all the numbers together, and all the variables
w^2-8w+16=0
a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$w=\frac{-b}{2a}=\frac{8}{2}=4$
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