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w2+3/2w+2=w/2
We move all terms to the left:
w2+3/2w+2-(w/2)=0
Domain of the equation: 2w!=0We add all the numbers together, and all the variables
w!=0/2
w!=0
w∈R
w2+3/2w-(+w/2)+2=0
We add all the numbers together, and all the variables
w^2+3/2w-(+w/2)+2=0
We get rid of parentheses
w^2+3/2w-w/2+2=0
We calculate fractions
w^2+2=0
a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation
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