w2+5w-63=0

Solution for w2+5w-63=0 equation:

w2+5w-63=0

We add all the numbers together, and all the variables

w^2+5w-63=0

a = 1; b = 5; c = -63;
Δ = b2-4ac
Δ = 52-4·1·(-63)
Δ = 277
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{277}}{2*1}=\frac{-5-\sqrt{277}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{277}}{2*1}=\frac{-5+\sqrt{277}}{2}
$