w=-9w2+5

Solution for w=-9w2+5 equation:

w=-9w^2+5

We move all terms to the left:

w-(-9w^2+5)=0

We get rid of parentheses

9w^2+w-5=0

a = 9; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·9·(-5)
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{181}}{2*9}=\frac{-1-\sqrt{181}}{18}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{181}}{2*9}=\frac{-1+\sqrt{181}}{18}
$