x((x+1)+(x+2))(x+3)=63

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Solution for x((x+1)+(x+2))(x+3)=63 equation: 


Simplifying
x((x + 1) + (x + 2))(x + 3) = 63

Reorder the terms:
x((1 + x) + (x + 2))(x + 3) = 63

Remove parenthesis around (1 + x)
x(1 + x + (x + 2))(x + 3) = 63

Reorder the terms:
x(1 + x + (2 + x))(x + 3) = 63

Remove parenthesis around (2 + x)
x(1 + x + 2 + x)(x + 3) = 63

Reorder the terms:
x(1 + 2 + x + x)(x + 3) = 63

Combine like terms: 1 + 2 = 3
x(3 + x + x)(x + 3) = 63

Combine like terms: x + x = 2x
x(3 + 2x)(x + 3) = 63

Reorder the terms:
x(3 + 2x)(3 + x) = 63

Multiply (3 + 2x) * (3 + x)
x(3(3 + x) + 2x * (3 + x)) = 63
x((3 * 3 + x * 3) + 2x * (3 + x)) = 63
x((9 + 3x) + 2x * (3 + x)) = 63
x(9 + 3x + (3 * 2x + x * 2x)) = 63
x(9 + 3x + (6x + 2x2)) = 63

Combine like terms: 3x + 6x = 9x
x(9 + 9x + 2x2) = 63
(9 * x + 9x * x + 2x2 * x) = 63
(9x + 9x2 + 2x3) = 63

Solving
9x + 9x2 + 2x3 = 63

Solving for variable 'x'.

Reorder the terms:
-63 + 9x + 9x2 + 2x3 = 63 + -63

Combine like terms: 63 + -63 = 0
-63 + 9x + 9x2 + 2x3 = 0

The solution to this equation could not be determined.

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