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x(-2x+3)=1/2
We move all terms to the left:
x(-2x+3)-(1/2)=0
We add all the numbers together, and all the variables
x(-2x+3)-(+1/2)=0
We multiply parentheses
-2x^2+3x-(+1/2)=0
We get rid of parentheses
-2x^2+3x-1/2=0
We multiply all the terms by the denominator
-2x^2*2+3x*2-1=0
Wy multiply elements
-4x^2+6x-1=0
a = -4; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-4)·(-1)
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{5}}{2*-4}=\frac{-6-2\sqrt{5}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{5}}{2*-4}=\frac{-6+2\sqrt{5}}{-8} $
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