If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(-3x+3)=0
We multiply parentheses
-3x^2+3x=0
a = -3; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-3)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-3}=\frac{-6}{-6} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-3}=\frac{0}{-6} =0 $
| 3x=24-9x | | 3(x-2)+1=2(x-4)+x+13 | | 4x+4=44-6x | | 3^2x-8(3^x)=0 | | 5c+4=3(c-5) | | -2d+1=9 | | 3/4+n=-5/2 | | 5x+10=3x-30 | | 8+4u=36 | | 4x-14=-10-2x | | 3k-6k=-27 | | 7/6x-4=19/6x+2 | | 1.5x+41=5x+6 | | 4f(3)=12 | | 5x-3=14x-24 | | 2x+19=35-2x | | 25s+27=5 | | 4x+12+2x=8x+8 | | 5q-(q-2)=2q+2(q+1 | | 3x+18=68-2x | | 2a+9=3a | | t+20=4t+8 | | 2^2x-1-6,2^x-1+4=0 | | 3*x+2=41 | | 0.30x=3.00 | | 8a-16=6a-28 | | Y=-2x+168 | | 1/2(x-6)-1/3(3-2x)=5/2x+2(1/3x+1) | | x2+7x-19=8 | | 3(2x+3)=2x+8 | | 32-4w=5w+5 | | (x/2)-8=18 |