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x(0.5x+6)=432
We move all terms to the left:
x(0.5x+6)-(432)=0
We multiply parentheses
0x^2+6x-432=0
We add all the numbers together, and all the variables
x^2+6x-432=0
a = 1; b = 6; c = -432;
Δ = b2-4ac
Δ = 62-4·1·(-432)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-42}{2*1}=\frac{-48}{2} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+42}{2*1}=\frac{36}{2} =18 $
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