If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(1/2x+3)=180
We move all terms to the left:
x(1/2x+3)-(180)=0
Domain of the equation: 2x+3)!=0We multiply parentheses
x∈R
x^2+3x-180=0
a = 1; b = 3; c = -180;
Δ = b2-4ac
Δ = 32-4·1·(-180)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-27}{2*1}=\frac{-30}{2} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+27}{2*1}=\frac{24}{2} =12 $
| (4x-7)(5x+2)(2x+4)=21 | | 4(4x+1)=-60 | | 70=x-0.025x | | 2m-6=-28 | | 24.53=5g+3.88 | | (1.74)(1-x)=x | | 0=28x | | 70=x-0.25x | | j-839=-496 | | -2v-38=-6(v+7) | | 4x+5+6x-5=90 | | 1+2x+7x=-17 | | 4-3x=+x | | -36=6(-5+x) | | -36=-6m+6 | | 2+5n=-63 | | 6x-12=2(36) | | 6x-12=2x36 | | -8(3x+8)=-256 | | 3(x-2)-2(x+1)=2(3x-5) | | x0.9=0.45 | | 2(x+7)=2(x+3) | | 4e+2=2e-10 | | 65x+53(6-x)=6 | | 19a=a+54 | | x+10+3x+20=90 | | -7(7-8x)=175 | | 9+5=3x+13 | | -4(x+5)=5/3)3x-12 | | 180=(7x+88)+(14x+60) | | -140=-4(7k-7) | | x^2+x^2+1)+6=0 |