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x(100+x)=2400
We move all terms to the left:
x(100+x)-(2400)=0
We add all the numbers together, and all the variables
x(x+100)-2400=0
We multiply parentheses
x^2+100x-2400=0
a = 1; b = 100; c = -2400;
Δ = b2-4ac
Δ = 1002-4·1·(-2400)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-140}{2*1}=\frac{-240}{2} =-120 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+140}{2*1}=\frac{40}{2} =20 $
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