x(10x+11)+3=0

Solution for x(10x+11)+3=0 equation:

x(10x+11)+3=0

We multiply parentheses

10x^2+11x+3=0

a = 10; b = 11; c = +3;
Δ = b2-4ac
Δ = 112-4·10·3
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-1}{2*10}=\frac{-12}{20}
=-3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+1}{2*10}=\frac{-10}{20}
=-1/2
$