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x(1200-2x)=0
We add all the numbers together, and all the variables
x(-2x+1200)=0
We multiply parentheses
-2x^2+1200x=0
a = -2; b = 1200; c = 0;
Δ = b2-4ac
Δ = 12002-4·(-2)·0
Δ = 1440000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1440000}=1200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1200)-1200}{2*-2}=\frac{-2400}{-4} =+600 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1200)+1200}{2*-2}=\frac{0}{-4} =0 $
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