x(15x+19)+4=0

Solution for x(15x+19)+4=0 equation:

x(15x+19)+4=0

We multiply parentheses

15x^2+19x+4=0

a = 15; b = 19; c = +4;
Δ = b2-4ac
Δ = 192-4·15·4
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-11}{2*15}=\frac{-30}{30}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+11}{2*15}=\frac{-8}{30}
=-4/15
$