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x(2)+3x=-(5)/(4)
We move all terms to the left:
x(2)+3x-(-(5)/(4))=0
We add all the numbers together, and all the variables
x^2+3x-(-5/4)=0
We get rid of parentheses
x^2+3x+5/4=0
We multiply all the terms by the denominator
x^2*4+3x*4+5=0
Wy multiply elements
4x^2+12x+5=0
a = 4; b = 12; c = +5;
Δ = b2-4ac
Δ = 122-4·4·5
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-8}{2*4}=\frac{-20}{8} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+8}{2*4}=\frac{-4}{8} =-1/2 $
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