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x(2)-17.5=12x
We move all terms to the left:
x(2)-17.5-(12x)=0
We add all the numbers together, and all the variables
x^2-12x-17.5=0
a = 1; b = -12; c = -17.5;
Δ = b2-4ac
Δ = -122-4·1·(-17.5)
Δ = 214
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{214}}{2*1}=\frac{12-\sqrt{214}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{214}}{2*1}=\frac{12+\sqrt{214}}{2} $
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