x(2)-42x=-441

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Solution for x(2)-42x=-441 equation: 



x(2)-42x=-441

We move all terms to the left:

x(2)-42x-(-441)=0

We add all the numbers together, and all the variables

x^2-42x+441=0

a = 1; b = -42; c = +441;
Δ = b2-4ac
Δ = -422-4·1·441
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{42}{2}=21$

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