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x(2)=x-5
We move all terms to the left:
x(2)-(x-5)=0
We add all the numbers together, and all the variables
x^2-(x-5)=0
We get rid of parentheses
x^2-x+5=0
We add all the numbers together, and all the variables
x^2-1x+5=0
a = 1; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·1·5
Δ = -19
Delta is less than zero, so there is no solution for the equation
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