x(2+3)-12=(-9+1)x+65+x2

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Solution for x(2+3)-12=(-9+1)x+65+x2 equation: 



x(2+3)-12=(-9+1)x+65+x2

We move all terms to the left:

x(2+3)-12-((-9+1)x+65+x2)=0

We add all the numbers together, and all the variables

x5-((-8)x+65+x2)-12=0

We add all the numbers together, and all the variables

x^5-((-8)x+65+x2)-12=0



We calculate terms in parentheses: -((-8)x+65+x2), so:

(-8)x+65+x2

determiningTheFunctionDomain
(-8)x+x2+65

We add all the numbers together, and all the variables

x^2+(-8)x+65

We multiply parentheses

x^2-8x+65

Back to the equation:

-(x^2-8x+65)



We do not support expression: x^5

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