x(2-3x)+10=2(x+5)

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Solution for x(2-3x)+10=2(x+5) equation: 


Simplifying
x(2 + -3x) + 10 = 2(x + 5)
(2 * x + -3x * x) + 10 = 2(x + 5)
(2x + -3x2) + 10 = 2(x + 5)

Reorder the terms:
10 + 2x + -3x2 = 2(x + 5)

Reorder the terms:
10 + 2x + -3x2 = 2(5 + x)
10 + 2x + -3x2 = (5 * 2 + x * 2)
10 + 2x + -3x2 = (10 + 2x)

Add '-10' to each side of the equation.
10 + 2x + -10 + -3x2 = 10 + -10 + 2x

Reorder the terms:
10 + -10 + 2x + -3x2 = 10 + -10 + 2x

Combine like terms: 10 + -10 = 0
0 + 2x + -3x2 = 10 + -10 + 2x
2x + -3x2 = 10 + -10 + 2x

Combine like terms: 10 + -10 = 0
2x + -3x2 = 0 + 2x
2x + -3x2 = 2x

Add '-2x' to each side of the equation.
2x + -2x + -3x2 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 + -3x2 = 2x + -2x
-3x2 = 2x + -2x

Combine like terms: 2x + -2x = 0
-3x2 = 0

Solving
-3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-3'.
x2 = 0

Simplifying
x2 = 0

Take the square root of each side:
x = {0}

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