x(2/3)=16.2

Solution for x(2/3)=16.2 equation:

x(2/3)=16.2

We move all terms to the left:

x(2/3)-(16.2)=0

We add all the numbers together, and all the variables

x(+2/3)-(16.2)=0

We add all the numbers together, and all the variables

x(+2/3)-16.2=0

We multiply parentheses

2x^2-16.2=0

a = 2; b = 0; c = -16.2;
Δ = b2-4ac
Δ = 02-4·2·(-16.2)
Δ = 129.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{129.6}}{2*2}=\frac{0-\sqrt{129.6}}{4}
=-\frac{\sqrt{}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{129.6}}{2*2}=\frac{0+\sqrt{129.6}}{4}
=\frac{\sqrt{}}{4}
$