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x(21+10x)=49
We move all terms to the left:
x(21+10x)-(49)=0
We add all the numbers together, and all the variables
x(10x+21)-49=0
We multiply parentheses
10x^2+21x-49=0
a = 10; b = 21; c = -49;
Δ = b2-4ac
Δ = 212-4·10·(-49)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-49}{2*10}=\frac{-70}{20} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+49}{2*10}=\frac{28}{20} =1+2/5 $
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