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x(2x+1)-5=2x(x+1)-x+1
We move all terms to the left:
x(2x+1)-5-(2x(x+1)-x+1)=0
We multiply parentheses
2x^2+x-(2x(x+1)-x+1)-5=0
We calculate terms in parentheses: -(2x(x+1)-x+1), so:We get rid of parentheses
2x(x+1)-x+1
We add all the numbers together, and all the variables
-1x+2x(x+1)+1
We multiply parentheses
2x^2-1x+2x+1
We add all the numbers together, and all the variables
2x^2+x+1
Back to the equation:
-(2x^2+x+1)
2x^2-2x^2+x-x-1-5=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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