x(2x+10)=132

Solution for x(2x+10)=132 equation:

X(2X+10)=132

We move all terms to the left:

X(2X+10)-(132)=0

We multiply parentheses

2X^2+10X-132=0

a = 2; b = 10; c = -132;
Δ = b2-4ac
Δ = 102-4·2·(-132)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-34}{2*2}=\frac{-44}{4}
=-11
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+34}{2*2}=\frac{24}{4}
=6
$