x(2x+12)=110

Solution for x(2x+12)=110 equation:

x(2x+12)=110

We move all terms to the left:

x(2x+12)-(110)=0

We multiply parentheses

2x^2+12x-110=0

a = 2; b = 12; c = -110;
Δ = b2-4ac
Δ = 122-4·2·(-110)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-32}{2*2}=\frac{-44}{4}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+32}{2*2}=\frac{20}{4}
=5
$