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x(2x+163)-6240000=0
We multiply parentheses
2x^2+163x-6240000=0
a = 2; b = 163; c = -6240000;
Δ = b2-4ac
Δ = 1632-4·2·(-6240000)
Δ = 49946569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(163)-\sqrt{49946569}}{2*2}=\frac{-163-\sqrt{49946569}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(163)+\sqrt{49946569}}{2*2}=\frac{-163+\sqrt{49946569}}{4} $
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