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x(2x+2)=-8
We move all terms to the left:
x(2x+2)-(-8)=0
We add all the numbers together, and all the variables
x(2x+2)+8=0
We multiply parentheses
2x^2+2x+8=0
a = 2; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·2·8
Δ = -60
Delta is less than zero, so there is no solution for the equation
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