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x(2x+3)=127.x=
We move all terms to the left:
x(2x+3)-(127.x)=0
We add all the numbers together, and all the variables
x(2x+3)-(+127.x)=0
We multiply parentheses
2x^2+3x-(+127.x)=0
We get rid of parentheses
2x^2+3x-127.x=0
We add all the numbers together, and all the variables
2x^2-124x=0
a = 2; b = -124; c = 0;
Δ = b2-4ac
Δ = -1242-4·2·0
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15376}=124$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-124)-124}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-124)+124}{2*2}=\frac{248}{4} =62 $
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