x(2x+3-x)=21

Solution for x(2x+3-x)=21 equation:

x(2x+3-x)=21

We move all terms to the left:

x(2x+3-x)-(21)=0

We add all the numbers together, and all the variables

x(x+3)-21=0

We multiply parentheses

x^2+3x-21=0

a = 1; b = 3; c = -21;
Δ = b2-4ac
Δ = 32-4·1·(-21)
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{93}}{2*1}=\frac{-3-\sqrt{93}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{93}}{2*1}=\frac{-3+\sqrt{93}}{2}
$