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x(2x+30)=4400
We move all terms to the left:
x(2x+30)-(4400)=0
We multiply parentheses
2x^2+30x-4400=0
a = 2; b = 30; c = -4400;
Δ = b2-4ac
Δ = 302-4·2·(-4400)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36100}=190$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-190}{2*2}=\frac{-220}{4} =-55 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+190}{2*2}=\frac{160}{4} =40 $
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