x(2x+4)=(2+1)(x-2)

Solution for x(2x+4)=(2+1)(x-2) equation:

x(2x+4)=(2+1)(x-2)

We move all terms to the left:

x(2x+4)-((2+1)(x-2))=0

We add all the numbers together, and all the variables

x(2x+4)-(3(x-2))=0

We multiply parentheses

2x^2+4x-(3(x-2))=0


We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)


We get rid of parentheses

2x^2+4x-3x+6=0

We add all the numbers together, and all the variables

2x^2+x+6=0

a = 2; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·2·6
Δ = -47
Delta is less than zero, so there is no solution for the equation