If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(2x+7)=270
We move all terms to the left:
x(2x+7)-(270)=0
We multiply parentheses
2x^2+7x-270=0
a = 2; b = 7; c = -270;
Δ = b2-4ac
Δ = 72-4·2·(-270)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-47}{2*2}=\frac{-54}{4} =-13+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+47}{2*2}=\frac{40}{4} =10 $
| F(x)=15x^2+9x | | 6.2=-8+x | | (x+1)^1/2+(x-2)^1/2=3 | | 2x^2+9x+56=0 | | 20.1-11.9=y | | -135=-3n+3(6n-5) | | 6m-10=8m-4 | | -2x10=-2(x+5) | | 4j-6=18 | | 2/27=x/15 | | x5/3=40 | | 6=10k=256 | | 38-18=10x | | 8^x=1/64 | | 3×+7x=200 | | 98=2(8n+1) | | 3x^2+7x+4=10 | | 10x(4x-7)=31 | | 52+m=41 | | x+1/6+x+5/4=1 | | 5x-3/4-2(3+2x)/3+2=0 | | 5x-(x-2)+7=-(2x-9)-8(3x+6) | | 2/3(x+6)=1/4(x+8) | | 30.24/4.77=x/5.3 | | -7x=3(3x+9) | | 3x^2-7x-2=8 | | 5x+3=-643.8 | | -5x-7(-2x+16)=184 | | (1+x)^(31/365)=0 | | X+25/25=2/3x | | −14(z−5)=−14z+70 | | 5x=3+x/2 |