x(2x-1)=(x+4)(2x-3)

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Solution for x(2x-1)=(x+4)(2x-3) equation: 



x(2x-1)=(x+4)(2x-3)

We move all terms to the left:

x(2x-1)-((x+4)(2x-3))=0

We multiply parentheses

2x^2-1x-((x+4)(2x-3))=0

We multiply parentheses ..

2x^2-((+2x^2-3x+8x-12))-1x=0



We calculate terms in parentheses: -((+2x^2-3x+8x-12)), so:

(+2x^2-3x+8x-12)

We get rid of parentheses

2x^2-3x+8x-12

We add all the numbers together, and all the variables

2x^2+5x-12

Back to the equation:

-(2x^2+5x-12)



We add all the numbers together, and all the variables

2x^2-1x-(2x^2+5x-12)=0

We get rid of parentheses

2x^2-2x^2-1x-5x+12=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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