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x(2x-2)=(2x+1)(x-3)
We move all terms to the left:
x(2x-2)-((2x+1)(x-3))=0
We multiply parentheses
2x^2-2x-((2x+1)(x-3))=0
We multiply parentheses ..
2x^2-((+2x^2-6x+x-3))-2x=0
We calculate terms in parentheses: -((+2x^2-6x+x-3)), so:We add all the numbers together, and all the variables
(+2x^2-6x+x-3)
We get rid of parentheses
2x^2-6x+x-3
We add all the numbers together, and all the variables
2x^2-5x-3
Back to the equation:
-(2x^2-5x-3)
2x^2-2x-(2x^2-5x-3)=0
We get rid of parentheses
2x^2-2x^2-2x+5x+3=0
We add all the numbers together, and all the variables
3x+3=0
We move all terms containing x to the left, all other terms to the right
3x=-3
x=-3/3
x=-1
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