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x(2x-24)=-70
We move all terms to the left:
x(2x-24)-(-70)=0
We add all the numbers together, and all the variables
x(2x-24)+70=0
We multiply parentheses
2x^2-24x+70=0
a = 2; b = -24; c = +70;
Δ = b2-4ac
Δ = -242-4·2·70
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4}{2*2}=\frac{20}{4} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4}{2*2}=\frac{28}{4} =7 $
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