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x(2x-255)=180
We move all terms to the left:
x(2x-255)-(180)=0
We multiply parentheses
2x^2-255x-180=0
a = 2; b = -255; c = -180;
Δ = b2-4ac
Δ = -2552-4·2·(-180)
Δ = 66465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{66465}=\sqrt{9*7385}=\sqrt{9}*\sqrt{7385}=3\sqrt{7385}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-255)-3\sqrt{7385}}{2*2}=\frac{255-3\sqrt{7385}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-255)+3\sqrt{7385}}{2*2}=\frac{255+3\sqrt{7385}}{4} $
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