x(2x-3)=(2x+1)(1x-4)

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Solution for x(2x-3)=(2x+1)(1x-4) equation: 



x(2x-3)=(2x+1)(1x-4)

We move all terms to the left:

x(2x-3)-((2x+1)(1x-4))=0

We add all the numbers together, and all the variables

x(2x-3)-((2x+1)(x-4))=0

We multiply parentheses

2x^2-3x-((2x+1)(x-4))=0

We multiply parentheses ..

2x^2-((+2x^2-8x+x-4))-3x=0



We calculate terms in parentheses: -((+2x^2-8x+x-4)), so:

(+2x^2-8x+x-4)

We get rid of parentheses

2x^2-8x+x-4

We add all the numbers together, and all the variables

2x^2-7x-4

Back to the equation:

-(2x^2-7x-4)



We add all the numbers together, and all the variables

2x^2-3x-(2x^2-7x-4)=0

We get rid of parentheses

2x^2-2x^2-3x+7x+4=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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