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x(2x-3)=104
We move all terms to the left:
x(2x-3)-(104)=0
We multiply parentheses
2x^2-3x-104=0
a = 2; b = -3; c = -104;
Δ = b2-4ac
Δ = -32-4·2·(-104)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-29}{2*2}=\frac{-26}{4} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+29}{2*2}=\frac{32}{4} =8 $
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