x(2x-4)+x(2x-3)=(4x+3)(x-2)

Solution for x(2x-4)+x(2x-3)=(4x+3)(x-2) equation:

x(2x-4)+x(2x-3)=(4x+3)(x-2)

We move all terms to the left:

x(2x-4)+x(2x-3)-((4x+3)(x-2))=0

We multiply parentheses

2x^2+2x^2-4x-3x-((4x+3)(x-2))=0

We multiply parentheses ..

2x^2+2x^2-((+4x^2-8x+3x-6))-4x-3x=0


We calculate terms in parentheses: -((+4x^2-8x+3x-6)), so:

(+4x^2-8x+3x-6)

We get rid of parentheses

4x^2-8x+3x-6

We add all the numbers together, and all the variables

4x^2-5x-6

Back to the equation:

-(4x^2-5x-6)


We add all the numbers together, and all the variables

4x^2-7x-(4x^2-5x-6)=0

We get rid of parentheses

4x^2-4x^2-7x+5x+6=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3