x(2x-4)=(2x+1)(x+2)

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Solution for x(2x-4)=(2x+1)(x+2) equation: 



x(2x-4)=(2x+1)(x+2)

We move all terms to the left:

x(2x-4)-((2x+1)(x+2))=0

We multiply parentheses

2x^2-4x-((2x+1)(x+2))=0

We multiply parentheses ..

2x^2-((+2x^2+4x+x+2))-4x=0



We calculate terms in parentheses: -((+2x^2+4x+x+2)), so:

(+2x^2+4x+x+2)

We get rid of parentheses

2x^2+4x+x+2

We add all the numbers together, and all the variables

2x^2+5x+2

Back to the equation:

-(2x^2+5x+2)



We add all the numbers together, and all the variables

2x^2-4x-(2x^2+5x+2)=0

We get rid of parentheses

2x^2-2x^2-4x-5x-2=0

We add all the numbers together, and all the variables

-9x-2=0

We move all terms containing x to the left, all other terms to the right

-9x=2

x=2/-9

x=-2/9

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