x(2x-4)=(2x+1)(x-5)

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Solution for x(2x-4)=(2x+1)(x-5) equation: 



x(2x-4)=(2x+1)(x-5)

We move all terms to the left:

x(2x-4)-((2x+1)(x-5))=0

We multiply parentheses

2x^2-4x-((2x+1)(x-5))=0

We multiply parentheses ..

2x^2-((+2x^2-10x+x-5))-4x=0



We calculate terms in parentheses: -((+2x^2-10x+x-5)), so:

(+2x^2-10x+x-5)

We get rid of parentheses

2x^2-10x+x-5

We add all the numbers together, and all the variables

2x^2-9x-5

Back to the equation:

-(2x^2-9x-5)



We add all the numbers together, and all the variables

2x^2-4x-(2x^2-9x-5)=0

We get rid of parentheses

2x^2-2x^2-4x+9x+5=0

We add all the numbers together, and all the variables

5x+5=0

We move all terms containing x to the left, all other terms to the right

5x=-5

x=-5/5

x=-1

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