x(2x-4)=(2x+2)(x-2)

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Solution for x(2x-4)=(2x+2)(x-2) equation: 



x(2x-4)=(2x+2)(x-2)

We move all terms to the left:

x(2x-4)-((2x+2)(x-2))=0

We multiply parentheses

2x^2-4x-((2x+2)(x-2))=0

We multiply parentheses ..

2x^2-((+2x^2-4x+2x-4))-4x=0



We calculate terms in parentheses: -((+2x^2-4x+2x-4)), so:

(+2x^2-4x+2x-4)

We get rid of parentheses

2x^2-4x+2x-4

We add all the numbers together, and all the variables

2x^2-2x-4

Back to the equation:

-(2x^2-2x-4)



We add all the numbers together, and all the variables

2x^2-4x-(2x^2-2x-4)=0

We get rid of parentheses

2x^2-2x^2-4x+2x+4=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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